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$slimegroyper

$slimegroyper

@pernia@cum.salon remote
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riddle me this, mercurial black @Merc

say a 13 year old girl walks into your dms asking for sex. you are a 25 year old man, but don't want her to lose hope and break her heart, as she is hopelessly in love with you. So you, being a principled man, tell her that the minimum age you would be willing to date is half your own age, plus seven.

how long must susie wait before she can date you and call you her man?
Dark Lord Merc :downey:

Dark Lord Merc :downey:

@Merc@freerobuxextremist.com remote
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@pernia

25 + x = 13 + (25 + x) / 2 + 7
25 + x = 20 + (25 + x)/2
5 + x = (25 + x)/2
10 + 2x = 25 + x
x = 15

(Desmos confirms that algebra)

40/2 + 7 = 27, though, rather than 28, so let's see what happens if we do x = 15 - ε

(40-ε)/2 + 7 = 27 - ε/2. Note, 15 - ε years have elapsed, giving her the age of 27 - ε. We have that 27 - ε/2 > 27 - ε, though, so she's still too young.

I think that checks out? Weird how discrete it is, though
Replying to @Merc@freerobuxextremist.com

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Replying to @Merc@freerobuxextremist.com
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$slimegroyper

$slimegroyper

@pernia@cum.salon remote
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@Merc i was thinking about this after watching a chris hansen video. ts problem is 100% modeling and 0.00001% math

you know your age difference is constant, and is 25 - 13 = 12

given x as your age and y as hers, you can model this with:

x - y = 12 (1)

given your principled constraint, you have

x/2 + 7 = y (2)

you solve for x:

x - 12 = y (1) => x - 12 = x/2 + 7 (2)

x = x/2 + 19 =>
x - x/2 = 19 =>
2x -x = 38 =>
x = 38 (your age)

x - y = 12 (1) => 38 - y = 12 => y = 26 (her age)

because the equations are satisfied in the future, you subtract your current ages

38 - 25 = 13

you have to wait 13 years to be together with your beloved wife susie

#appliedmath